Model 2 Formula method ‘M1D1W1 = M2D2W2’ Practice Questions Answers Test with Solutions & More Shortcuts

Question : 11 [SSC MTS 2013]

Stanie and Paul take a piece of work for Rs.28,800. One alone could do it in 36 days, the other in 48 days. With the assistance of an expert, they finish it in 12 days. How much remuneration the expert should get ?

a) Rs.10000

b) Rs.18000

c) Rs.12000

d) Rs.16000

Answer: (c)

Expert’s 1 day’s work

= $1/12 - 1/36 - 1/48$

= ${12 - 4 - 3}/144 = 5/144$

Ratio of their respective work for 1 day

= $1/36 : 1/48 : 5/144$ = 4 : 3 : 5

Expert’s share

= $5/12 × 28800$ = 12000

Question : 12 [SSC CGL Prelim 2004]

A alone can do a piece of work in 6 days and B alone in 8 days. A and B undertook to do it for Rs.3200. With the help of C they completed the work in 3 days. How much is to be paid to C ?

a) Rs.375

b) Rs.400

c) Rs.800

d) Rs.600

Answer: (b)

Using Rule 25,

A’s 1 day’s work = $1/6$

B’s 1 day’s work = $1/8$

(A + B + C)’s 1 day’s work = $1/3$

C’s 1day’s work

= $1/3 - 1/6 - 1/8 = {8 - 4 - 3}/24 = 1/24$

Ratio of their one day’s work respectively

= $1/6 : 1/8 : 1/24$ = 4 : 3 : 1

Sum of the ratios = 4 + 3 + 1 = 8

C’s share = Rs.$1/8$ × 3200 = Rs.400

Question : 13 [SSC CGL Tier-I 2013]

A sum of money is sufficient to pay A’ s wages for 21 days and B’s wages for 28 days. The same money is sufficient to pay the wages of both for :

a) 12$1/4$ days

b) 14 days

c) 12 days

d) 24$1/2$ days

Answer: (c)

A's 1 day's work = $1/21$

B's 1 day's work = $1/28$

Total work done by both

= $1/21 + 1/28 = {4 + 3}/84 = 1/12$

Amount is sufficient to pay 12 days wages of both.

Using Rule 2
If A completes a piece of work in 'x' days, and B completes the same work in 'y' days, then,
Work done by A in 1 day = $1/x$, Work done by B in 1 day = $1/y$
Work done by A and B in 1 day = $1/x + 1/y = {x + y}/{xy}$
Total time taken to complete the work by A and B both = $({xy}/{x + y})$

Here, x = 21, y = 28

Required days

= ${xy}/{x + y}= {21 × 28}/{21 + 28}$

= ${21 × 28}/49$ = 12 days

Question : 14 [SSC CGL Prelim 1999]

Suman can do a work in 3 days. Sumati can do the same work in 2 days. Both of them finish the work together and get Rs.150. What is the share of Suman ?

a) Rs.30

b) Rs.60

c) Rs.75

d) Rs.70

Answer: (b)

Ratio of Suman’s and Sumati’s 1 day’s work

= $1/3 : 1/2 = 2 : 3$

Sum of the ratios = 2 + 3 = 5

Suman’s share = $2/5 × 150$ = Rs.60

Using Rule 24
A can do a work in 'm' days and B can do the same work in 'n' days. If they work together and total wages is R, then.
Part of A = $n/{m + n} × R$
Part of B = $m/{m + n} × R$

Here, m = 3, n = 2, R = 150

Share of suman = $n/{m + n} × R$

= $2/{3 + 2} × 150 = 2/5 × 150$ = 60

Question : 15 [SSC CGL Prelim 2004]

A and B can complete a piece of work in 15 days and 10 days respectively. They contracted to complete the work for Rs.30,000. The share of A in the contracted money will be :

a) Rs.18,000

b) Rs.16,500

c) Rs.12,000

d) Rs.12,500

Answer: (c)

A’s 1 day’s work = $1/15$

B’s 1 day’s work = $1/10$

Ratio = $1/15 : 1/10$ = 2 : 3

Sum of the ratios = 2 + 3 = 5

A’s share

= Rs.$2/5 × 30000$ = Rs.12000

Using Rule 24,

Here, m = 15, n = 10, R = 30,000

Share of A = $n/{m + n} × R$

= $10/{15 + 10} × 30000$

= $10/25 × 30 000$ = Rs.12,000

IMPORTANT quantitative aptitude EXERCISES

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